F(-5)=4(-5)^2+x-5

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Solution for F(-5)=4(-5)^2+x-5 equation: 



(-5)=4(-5)^2+F-5

We move all terms to the left:

(-5)-(4(-5)^2+F-5)=0

We add all the numbers together, and all the variables

-(4(-5)^2+F-5)-5=0



We calculate terms in parentheses: -(4(-5)^2+F-5), so:

4(-5)^2+F-5

determiningTheFunctionDomain
F-5+4(-5)^2

We add all the numbers together, and all the variables

F+95

Back to the equation:

-(F+95)



We get rid of parentheses

-F-95-5=0

We add all the numbers together, and all the variables

-1F-100=0

We move all terms containing F to the left, all other terms to the right

-F=100

F=100/-1

F=-100

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